3x^2=0,92

Solution for 3x^2=0,92 equation:

3x^2=0.92

We move all terms to the left:

3x^2-(0.92)=0

We add all the numbers together, and all the variables

3x^2-0.92=0

a = 3; b = 0; c = -0.92;
Δ = b2-4ac
Δ = 02-4·3·(-0.92)
Δ = 11.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{11.04}}{2*3}=\frac{0-\sqrt{11.04}}{6}
=-\frac{\sqrt{}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{11.04}}{2*3}=\frac{0+\sqrt{11.04}}{6}
=\frac{\sqrt{}}{6}
$